w^2+150w+5625=0

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Solution for w^2+150w+5625=0 equation: 



w^2+150w+5625=0

a = 1; b = 150; c = +5625;
Δ = b2-4ac
Δ = 1502-4·1·5625
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{-150}{2}=-75$

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